0=m^2-4m+23

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Solution for 0=m^2-4m+23 equation: 



0=m^2-4m+23

We move all terms to the left:

0-(m^2-4m+23)=0

We add all the numbers together, and all the variables

-(m^2-4m+23)=0

We get rid of parentheses

-m^2+4m-23=0

We add all the numbers together, and all the variables

-1m^2+4m-23=0

a = -1; b = 4; c = -23;
Δ = b2-4ac
Δ = 42-4·(-1)·(-23)
Δ = -76
Delta is less than zero, so there is no solution for the equation

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